Posted by **Jake** on Wednesday, January 27, 2010 at 5:24pm.

R is the region in the plane bounded below by the curve y=x^2 and above by the line y=1.

(a) Set up and evaluate an integral that gives the area of R.

(b) A solid has base R and the cross-sections of the solid perpendicular to the y-axis are squares. Find the volume of the solid.

(c) A solid has base R and the cross-sections of the solid perpendicular to the y-axis are equilateral triangles. Find the volume of the solid.

## Answer This Question

## Related Questions

- Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
- Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
- calculus - Set up, but do not evaluate, the integral which gives the volume when...
- math - The region R, is bounded by the graphs of x = 5/3 y and the curve C given...
- math - The region R, is bounded by the graphs of x = 5/3 y and the curve C given...
- MATH-HELP! - The region R, is bounded by the graphs of x = 5/3 y and the curve C...
- why won't anybody help me - The region R, is bounded by the graphs of x = 5/3 y ...
- calculus - 1. Find the area of the region bounded by f(x)=x^2 +6x+9 and g(x)=5(x...
- Calculus AB - Let R be the region bounded by the graphs of y=sin(pi x) and y=(x^...
- Calculus check - The functions f and g are given by f(x)=sqrt(x^3) and g(x)=16-...

More Related Questions