physics
posted by jibjab .
The figure below shows two points in an Efield: Point 1 is at (x1,y1) = (9,4) in m, and Point 2 is at (x2,y2) = (13,9) in m. The Electric Field is constant, with a magnitude of 56.0 V/m, and is directed parallel to the +xaxis. The potential at point 1 is 1100 V. Calculate the potential at point 2

The potential difference equals the Efield multiplied by the difference in the x coordinate between the two points (which is 4 m).
The potential is greatest at the Point 1. work must be done against the field to move from from 2 to 1.