What s radical 20 is written in simplest radical for, the result is k radical 5. What is the value of k?
√20
=√(k²*5)
=k√5
So your task is to find k such that
20=k²*5
Can you take it from here?
To determine the value of k in the expression "k√5", where √20 is written in simplest radical form as "k√5", we need to find the value of k.
To solve this, let's simplify √20:
1. The prime factorization of 20 is 2 * 2 * 5.
2. Taking out pairs from the square roots, we have √(2 * 2 * 5).
3. Simplifying, we get √(2 * 2) * √5.
4. Further simplifying, we have 2√5.
Comparing this with the given expression "k√5", we can see that "k" is equal to 2.
Therefore, the value of k is 2 in the expression "k√5".