The length of a rectangle is fixed at 24 cm. What widths will make the perimeter greater than 7c cm?
The width must be greater than:
must be a typo
since the length is 24 cm, the perimeter must be greater than 48 cm
Sorry it said greater than 76 cm not 7c.
2L + 2W < 76
Insert your value for L and solve for W.
I hope this helps.
Thanks I think it did...just to be sure:
2(24) +2w< 76
48 +2w <76
2w < 28
w < 14
So the answer would be 14
To find the widths that will make the perimeter greater than 7 cm, we need to know the formula for calculating the perimeter of a rectangle. The perimeter (P) of a rectangle is given by the formula:
P = 2(length + width)
Given that the length of the rectangle is fixed at 24 cm, we can substitute this value into the formula:
7 = 2(24 + width)
Now we can solve for the width. First, simplify the equation:
7 = 48 + 2width
Next, isolate the 2width term:
2width = 7 - 48
2width = -41
Finally, solve for the width:
width = -41/2
Therefore, the width must be greater than -41/2 cm to make the perimeter greater than 7 cm. However, in practical terms, a negative width does not make sense for a rectangle, so we can conclude that there are no valid widths that will make the perimeter greater than 7 cm in this scenario.