an aircraft flew at 400km/h to its destination and returned at 500km/h. If the total trip took 9h, how far did it fly?

The answer is 2000km but how

distancethere=400*t

distanceback=500(9-t)
but the distances are the same
400t=500*9-500t
900t=5*900
t= 5 hrs
distance there= 400*5=2000km

Wtf I dont get it

I thought it was 1050?????

To find the distance the aircraft flew, we can use the formula:

Distance = Speed × Time

Let's break down the problem into two parts: the outbound trip and the return trip.

For the outbound trip:
Speed = 400 km/h
Time = T (unknown)

For the return trip:
Speed = 500 km/h
Time = 9 hours - T (since the total trip took 9 hours, the time for the return trip can be represented as the difference between the total trip time and the time of the outbound trip)

Now, we can set up two equations using the distance formula for both parts of the trip:

1) Outbound trip distance: Distance1 = Speed1 × Time1
2) Return trip distance: Distance2 = Speed2 × Time2

Since the distance covered in both parts of the trip is the same (as it is a round trip), we can set the two distances equal to each other:

Distance1 = Distance2

Speed1 × Time1 = Speed2 × Time2

Substituting the values:
400 km/h × T = 500 km/h × (9 hours - T)

Now, let's solve for T:

400T = 500(9 - T)
400T = 4500 - 500T
900T = 4500
T = 4500 / 900
T = 5 hours

Now that we know the time for the outbound trip (T = 5 hours), we can substitute it back into one of the distance formulas to find the distance:

Distance1 = Speed1 × Time1
Distance1 = 400 km/h × 5 hours
Distance1 = 2000 km

Therefore, the aircraft flew a total distance of 2000 km.