A tiny 0.60g ball carries a charge of magnitude f 8.0uC. It is suspended by a thread in a downward 300 N/C electric field. What is the tension in the thread if the charge on the ball is negative? - Positive?
Tension= mg+electric force
The direction of the E field is the direction of a positive charge, so if the charge is positive, they add.
If the charge is negative, they are in opposite directions.
Good
Answer
Please I want answer to my question
To calculate the tension in the thread, we need to consider the force acting on the charged ball in the electric field.
When the charge on the ball is negative, it experiences a force in the opposite direction to the electric field. The force on a charged particle in an electric field is given by the equation:
F = q * E,
where F is the force, q is the charge, and E is the electric field.
In this case, the electric field is 300 N/C, and the charge is -8.0 μC (-8.0 × 10^-6 C). Therefore, the force on the ball is:
F = (-8.0 × 10^-6 C) * (300 N/C) = -2.4 × 10^-3 N.
Since the ball is suspended in equilibrium, the tension in the thread is equal to the weight of the ball. We can calculate the weight using the formula:
Weight = mass * gravitational acceleration,
where the mass of the ball is 0.60 g (0.60 × 10^-3 kg) and the gravitational acceleration is 9.8 m/s^2.
Weight = (0.60 × 10^-3 kg) * (9.8 m/s^2) = 5.88 × 10^-3 N.
Thus, the tension in the thread when the charge on the ball is negative is 5.88 × 10^-3 N.
If the charge on the ball is positive, the force will be in the same direction as the electric field. Therefore, the calculations will be the same, and the tension in the thread will also be 5.88 × 10^-3 N.
The tension in the thread does not depend on the sign of the charge but rather on the magnitude of the charge and the electric field.