Posted by **BRENDON** on Tuesday, January 26, 2010 at 4:16pm.

24 1c coins are set out in a row on a table. Then

every 2nd coin is replaced by a 2c coin

every 3rd coin is replaced by a 5c coin

every 4th coin is replaced by a 10c coin

every 5th coin is replaced by a 20c coin

every 6th coin is replaced by a 50c coin

every 7th coin is replaced by a $1 coin

After all the exchanges have been carried out, what is the total amount left on the table?

Please help, the answer suppose to be $6.30 but I got $7.04?

Thank you

- MATH -
**bobpursley**, Tuesday, January 26, 2010 at 4:30pm
In the end, you have the following values:

coin value

7 $1

14 $1

21 $1

6 .50

12 .50

18 .50

24 .50

5 .20

10 .20

15 .20

20 .20

4 .1

8 .1

16 .1

2 .05

22 .05

the remaining all are .01

I count 16 above out of 24 coins, or .01*8

check my thinking.

- MATH -
**mariela**, Tuesday, January 26, 2010 at 4:31pm
you are wrong it is 6.30 thats what i got

- MATH -
**BRENDON**, Tuesday, January 26, 2010 at 5:02pm
Hi Mariela, could you please tell me how you got $6.30. Explanation above still added over $6.30, I'm confused.

Thanks

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