Posted by **Stella** on Tuesday, January 26, 2010 at 4:44am.

The region R is defined by 1(</=)x(</=)2 and 0(</=)y(</=)1/(x^3).

Find the number 'b' such that the line y=b divides R into two parts of equal area.

- calculus -
**drwls**, Tuesday, January 26, 2010 at 5:49am
Evaluate the integral of 1/x^3 from x = 1 to x = 2. That is the enclosed area of the region. I get 3/8. See what you get.

Then pick the upper limit of integration, b, such that the integral of 1/x^3 from 1 to b is half the number you got for the full integral.

## Answer this Question

## Related Questions

- calculus - The region R is defined by 1(</=)x(</=)2 and 0(</=)y(</=)...
- CALCULUS problem - There are four parts to this one question, and would really ...
- calc - 1. Let R be the region bounded by the x-axis, the graph of y=sqr(x) , and...
- Calculus - The region R is bounded by the x-axis, x = 1, x = 3, and y = 1/x^3 A...
- Calculus - Find the number b such that the line y = b divides the region bounded...
- calculus - Find the number b such that the line y = b divides the region bounded...
- calculus - Find the number b such that the line y = b divides the region bounded...
- cal 2 - Find the number b such that the line y = b divides the region bounded by...
- Calculus - Let R be the region in the first quadrant under the graph of y=1/sqrt...
- Calculus - Let R be the region bounded by y = 1/x, the lime x = 1, the line x = ...

More Related Questions