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November 26, 2014

November 26, 2014

Posted by **Will** on Tuesday, January 26, 2010 at 12:13am.

I know that the average value = (1/b-a)integrate from a to b f(x)dx

- calculus -
**drwls**, Tuesday, January 26, 2010 at 12:31amYou have stated the definition of the average value correctly. All you have to do is perform the integration and divide the integral by the integration interval, 2.

The indefinite integral of e^(-nx) is (-1/n)*e^(-nx).

The definite integral from -1 to 1 is

(-1/n)[e^-n - e^n]

Divide that by 2 for the average value.

Check my math. I am often sloppy.

- calculus -
**Will**, Tuesday, January 26, 2010 at 12:45amthanks, but can we leave it in that form?

- calculus -
**drwls**, Tuesday, January 26, 2010 at 10:03amYou can convert my answer to a hyperbolic sine of n, divided by 2, if you wish.

- calculus -
**drwls**, Tuesday, January 26, 2010 at 10:03amI meant "divided by n", not 2

- calculus -
**Will**, Tuesday, January 26, 2010 at 7:06pmWhat is hyperbolic sin of n? Never heard of that.

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