algebra
posted by Zouhoer on .
I would like to have some help on this problem please. I'm so post to find the vertex and axis of the parabola.Does anyone have an idea?
Y=x²16x+63.
A)vertex(8,1)axis=x=8
B)vertex(8,1)axis=x=8
C)vertex(8,1)axis=x=8
D)vertex(8,1)axis=x=8

x^216x= y63
x^2  16x + 64 = y+6463
(x8)^2 = y+1
symmetric about the vertical axis x = 8
when x = 8, y = 1