what is an equation of the line that passes through the point (4,-6) and has a slope of -3?
a) y=-3x+6
b) y=-3x-6
c) y=-3x+10
d) y=-3x+14
i don't get this question at all.
To find the equation of the line that passes through the point (4, -6) and has a slope of -3, you can use the point-slope formula. The point-slope formula is given by:
y - y1 = m(x - x1)
where (x1, y1) is the given point and m is the slope.
In this case, (x1, y1) = (4, -6) and m = -3. Plugging these values into the formula, we get:
y - (-6) = -3(x - 4)
Simplifying the equation:
y + 6 = -3x + 12
Now, we can rearrange the equation to solve for y:
y = -3x + 12 - 6
Simplifying further:
y = -3x + 6
Comparing this equation with the given options, we can see that the correct answer is:
a) y = -3x + 6
y= mx+b
you are given m
so put in (4,-6)into the equation, and solve for b.
that is the equatiom of the line