If a right triangle has a base of 4 inches and a height of 3 inches, make an equivilant triangle with a base of 17 inches. Can someone explain how to figure this answer?

3/4 = x/17

Solve for x to get the remaining dimension of the larger equivalent triangle.

I hope this helps.

To create an equivalent triangle with a base of 17 inches, we need to determine the corresponding height. The original triangle and the equivalent triangle will have similar shapes, meaning they have the same angles.

In a right triangle, the base and height are related by the equation A = (1/2) * base * height, where A represents the area of the triangle.

Let's first find the area of the original triangle with a base of 4 inches and a height of 3 inches:
A = (1/2) * 4 * 3
A = 6 square inches

Now, to find the height of the equivalent triangle with a base of 17 inches, we need to set up the same area equation and solve for the height:
A = (1/2) * 17 * height (let's call the height h)

Since the area of the equivalent triangle should be equal to 6 square inches, we can set up the equation:
6 = (1/2) * 17 * h

To isolate h, we can multiply both sides of the equation by 2/17:
12/17 = h

So, the equivalent triangle with a base of 17 inches will have a height of 12/17 inches.