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September 2, 2014

September 2, 2014

Posted by **kate** on Monday, January 25, 2010 at 8:11pm.

tan delta=-0.75

- pre calc -
**MathMate**, Monday, January 25, 2010 at 8:18pmThe domain of tan(x) is from -π/2 to π/2. So the reference angle for tan(δ)=-0.75 is between -&pi/2; to 0.

Having found the reference angle δ (approx. -0.64 radians), the general solution will be

δ+kπ where k=an integer.

- pre calc -
**kate**, Monday, January 25, 2010 at 8:22pmso what will be the solution

- pre calc -
**MathMate**, Monday, January 25, 2010 at 11:17pmA pre-calculus answer is -0.64 + kπ radians, where k∈ℤ.

- pre calc -
**MathMate**, Monday, January 25, 2010 at 11:20pmThe reason for the kπ is because tangent is a periodic function, with period equal to π radians.

Also, for your solution, you will need to evaluate more accurately (accuracy according to instructions, 3-4 decimals normally) the value of arctan(-0.75).

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