Friday

September 19, 2014

September 19, 2014

Posted by **rich** on Monday, January 25, 2010 at 7:28am.

- math -
**MathMate**, Monday, January 25, 2010 at 7:40amThis problem can be solved by working out the fraction of work done by each worker in one hour.

For A, fraction of work done per hour is 1/3.

For B, 1/4.

For C, 1/6.

If they all work together, in one hour they would have done

(1/3+1/4+1/6)

= (4+3+2)/12

= 9/12

= 3/4

of the work.

So if they paint together, it would take them 1/(3/4) = 4/3 days.

**Answer this Question**

**Related Questions**

Math - If it takes painter # 1 three hours to paint a house, and painter # 2 ...

Intermediate Algebra - Joe can paint a room in 6 hours while Sue can paint the ...

Math - A painter can paint a racquetball court in 8 hours. His assistant needs ...

Intermediate Algebra - A painter can paint a fence in 12 hours working alone. ...

Intermediate Algebra - A painter can paint a fence in 12 hours working alone. ...

Math - A painter needs 3 days to paint the walls of a room. How long would it ...

Math - A painter needs 3 days to paint the walls of a room. How long would it ...

Math - Al can paint a room in a hours working alone. Bill can paint a room in b ...

math - nadia can paint a room in 5 hours Nat can paint the same room in 7 hours ...

math - Arthur can paint a room in 6 hours. Boris can paint the same room in 8 ...