Monday

March 30, 2015

March 30, 2015

Posted by **rich** on Monday, January 25, 2010 at 7:28am.

- math -
**MathMate**, Monday, January 25, 2010 at 7:40amThis problem can be solved by working out the fraction of work done by each worker in one hour.

For A, fraction of work done per hour is 1/3.

For B, 1/4.

For C, 1/6.

If they all work together, in one hour they would have done

(1/3+1/4+1/6)

= (4+3+2)/12

= 9/12

= 3/4

of the work.

So if they paint together, it would take them 1/(3/4) = 4/3 days.

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