Friday

November 28, 2014

November 28, 2014

Posted by **Brendan** on Monday, January 25, 2010 at 1:47am.

A 12,000 kg railroad car traveling at a speed of 19 m/s strikes an identical car at rest. If the cars lock together as a result of the collision, what is their common speed afterward?

What would my x axis be and what would my y axis be ?

- physics -
**drwls**, Monday, January 25, 2010 at 2:02amThey are not asking you to graph the collision. All you need to do is apply a momentum conservation formula to compute a final speed.

The final speed is half the initial speed of the moving car.

**Answer this Question**

**Related Questions**

Physics - A 10,000 kg railroad car traveling at a speed of 24.0 m/s strikes an ...

Physics - A 10,000 kg railroad car traveling at a speed of 24.0 m/s strikes an ...

Physics - A 1424-kg railroad car traveling at a speed of 11 m/s strikes an ...

Physics ~ CONSERVATION OF MOMENTUM~ - 1.) A 10,000 kg railroad car traveling at ...

Physics ~ CONSERVATION OF MOMENTUM ~ - 1.) A 10,000 kg railroad car traveling at...

physics - a 9000 kg railroad car moving at 3 m/s strikes a stationary 5000 kg ...

Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...

Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...

Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...

Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...