Posted by Angie on .
A block of mass m1 = 4.1 kg rests on a frictionless horizontal surface. A second block of mass m2 = 1.7 kg hangs from an ideal cord of negligible mass that runs over an ideal pulley and then is connected to the first block. The blocks are released from rest.
(a) Find the acceleration of the two blocks after they are released. block 1: What is magnitude and direction?
block 2: What is magnitude and direction?
(b) What is the velocity of the first block 1.4 s after the release of the blocks, assuming the first block does not run out of room on the table and the second block does not land on the floor?
What is magnitude and direction?
(c) How far has block 1 moved during the 1.4-s interval? in meters
(d) What is the displacement of the blocks from their initial positions 0.50 s after they are released? block 1: Find magnitude and direction
block 2: find magnitude and direction
a). The direction should be obvious. Block m1 slides horizontally and Block m2 falls vertically. For the acceleration, a, write free body Newton's-law equations for each blcok separately, with the connecting cord tension T acting on both. Eliminate T and solve for a. Both blocks accelerate at the same rate, but in different directions.
b) velocity = a t (horizontal direction)
c) Displacement = (1/2) a t^2
d) Use the same formula as (c) but different time t
Do the calculations yourself and learn the method.