posted by Alexandra on .
Let's say that you find a slope of 6.671×10-14 for square plates of width 11.5 cm. What do you get for the value of the permittivity of free space?
what slope are you talking about? What is being plotted?
Im not really sure, that is all that as being asked.
Maybe it has to do with this first question as well?.... The electric field near the surface of a uniformly charged conducting plane can be determined by Gauss's law (look it up). If the plane is a square of sides 11.5 cm and carries a charge of 22.0 nC (that's nanocoulombs), what is the magnitude of the electric field near the surface?
(-5.00 + 1.00 j)/( 5.00 + 2.00 j )=