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December 20, 2014

December 20, 2014

Posted by **Tracy** on Sunday, January 24, 2010 at 9:10pm.

3tan^2x = 3^1/2 tan x

I have no idea how to approach this problem.

- calculus -
**drwls**, Sunday, January 24, 2010 at 9:36pm3^1/2 tan x *(3^1/2*tanx - 1)= 0

tan x = 0 or 1/sqrt3

x = 0, pi, pi/6 and one other tan^-1(1/sqrt3)

- calculus -
**Reiny**, Sunday, January 24, 2010 at 9:40pm3tan^2x = 3^1/2 tan x

3tan^2x - √3tan x = 0

tanx(3tanx - √3) = 0

so tanx = 0 or tanx = √3/3

if tanx = 0, then x = 0º, 180º, 360º, ...

if tanx = √3/3 then x = 30º, 210º,390º, ...

The period of the tangent function is 180º, so adding 180 to any of our answers produces more answers

the angles in radians would be

0, pi, 2pi ...

pi/6, 7pi/6, 13pi/6, ..

(adding pi each time)

- calculus -
**Anonymous**, Monday, January 25, 2010 at 12:16amMuch appreciated guys.

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