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January 29, 2015

January 29, 2015

Posted by **April** on Sunday, January 24, 2010 at 7:37pm.

I got that variance-34.2, but I'm unsure. Any help? Thanks.

- math -
**Reiny**, Sunday, January 24, 2010 at 8:16pmlook at his page.

http://davidmlane.com/hyperstat/A16252.html

- Reiny -
**April**, Sunday, January 24, 2010 at 8:25pmI looked at that page and did my problem according to the example, but the answer I got wasn't even a choice. Can you help al ittle more please?

- math -
**Reiny**, Sunday, January 24, 2010 at 8:36pmdid you get a mean of 10.8 ?

My squared differences were:

96.04, 27.04,7.84,38.44,1.44

that sum/5 = 34.16 which is the variance^2

so the variance = √34.16 = 5.845

notice that there is difference in the calculation depending on whether you divide by N or N-1.

Your text or your course should tell you which method to use.

- math -
**April**, Sunday, January 24, 2010 at 8:54pmNo. I thought mean was adding up the numbers and then dividing by how many numbers.

So .51+.44+.04+.01=1 divided by 4=.25

- math -
**Reiny**, Sunday, January 24, 2010 at 9:51pm(1 + 16 + 8 + 17 + 12)/5 = 10.8

mmmmh?

where did you get your numbers from ????

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