Posted by April on Sunday, January 24, 2010 at 7:37pm.
look at his page.
http://davidmlane.com/hyperstat/A16252.html
I looked at that page and did my problem according to the example, but the answer I got wasn't even a choice. Can you help al ittle more please?
did you get a mean of 10.8 ?
My squared differences were:
96.04, 27.04,7.84,38.44,1.44
that sum/5 = 34.16 which is the variance^2
so the variance = √34.16 = 5.845
notice that there is difference in the calculation depending on whether you divide by N or N-1.
Your text or your course should tell you which method to use.
No. I thought mean was adding up the numbers and then dividing by how many numbers.
So .51+.44+.04+.01=1 divided by 4=.25
(1 + 16 + 8 + 17 + 12)/5 = 10.8
mmmmh?
where did you get your numbers from ????
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