Posted by **Janie** on Sunday, January 24, 2010 at 7:04pm.

2cos^2Beta-Cosbeta=0 (find all solutions for the equation in the interval 0, 2 pi). I have no idea how to go about doing this. Do you isolate the beta on one side? Would you be able to show me how and I'll solve for you to check?

- Trig -
**Damon**, Sunday, January 24, 2010 at 7:12pm
cos B (2 cos B - 1 )=0

cos B = 0 is one solution. That is at pi/2 and 3pi/2

cos B = 1/2 is also a solution

that is at 60 degrees and -60 degrees which is at pi/3 and 5 pi/3

- Trig -
**Janie**, Sunday, January 24, 2010 at 7:35pm
I thought cos=1/2 at 30, not 60

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