Posted by **Janie** on Sunday, January 24, 2010 at 7:04pm.

2cos^2Beta-Cosbeta=0 (find all solutions for the equation in the interval 0, 2 pi). I have no idea how to go about doing this. Do you isolate the beta on one side? Would you be able to show me how and I'll solve for you to check?

- Trig -
**Damon**, Sunday, January 24, 2010 at 7:12pm
cos B (2 cos B - 1 )=0

cos B = 0 is one solution. That is at pi/2 and 3pi/2

cos B = 1/2 is also a solution

that is at 60 degrees and -60 degrees which is at pi/3 and 5 pi/3

- Trig -
**Janie**, Sunday, January 24, 2010 at 7:35pm
I thought cos=1/2 at 30, not 60

## Answer this Question

## Related Questions

- Trig. - Can someone please help me with this? Find all solutions to the equation...
- Pre-Calculus - Find all solutions to the equation in the interval [0, 2pi) cos4x...
- trig - how can i find all the exact solutions to the equation : 2cos^2x + 3sinx...
- trigonometry - Find all solutions on the interval [0.2pi) A) -3sin(t)=15cos(t)...
- Math (Calc) - Find all solutions to the following equation on the interval 0<...
- trig - Find all solutions to the equation 2cos(2x) = x + 1, correct to 4 ...
- Precalculus - Please help!!!!!!!!!!! Find all solutions to the equation in the ...
- math - If alpha and beta are the zeroes of the polynomial f (x) = 5y square -7y...
- trig - Find the solutions to the equation cos2x=sinx and 2cos^2x-3cosx-3=0
- trig - Find ALL solutions to the equation on the interval [0, 2pie]: 2sin(1/2X...

More Related Questions