The mass of a car is 2400 kg. the constant power supplied by the engine is 60 kW and the car starts from rest. What is the speed of the car at the end of 2 seconds?

derp 10 m/s

We know the power (6x10^4 Watts), and that power equals work over time. If you solve for the work, you get 1.2x10^5 Joules. Work is a form of energy, and if you set the initial kenetic energy (0 joules) plus the work done by the engine equal to the final kenetic energy you can solve for the final velocity.

To find the speed of the car at the end of 2 seconds, we can use the concept of work and energy.

Step 1: Find the work done by the engine.

The work done by the engine is equal to the power supplied multiplied by the time taken:
Work = Power * Time

Given that the constant power supplied by the engine is 60 kW and the time taken is 2 seconds:
Work = 60,000 W * 2 s = 120,000 J

Step 2: Determine the change in kinetic energy.

The work done by the engine is equal to the change in kinetic energy of the car:
Work = ΔKE

The change in kinetic energy is given by:
ΔKE = (1/2) * Mass * (Final Velocity^2 - Initial Velocity^2)

Since the car starts from rest, the initial velocity is 0, so the equation simplifies to:
ΔKE = (1/2) * Mass * Final Velocity^2

Step 3: Solve for the final velocity.

Substituting the known values into the equation, we have:
120,000 J = (1/2) * 2400 kg * Final Velocity^2

To find the Final Velocity, we rearrange the equation:
Final Velocity^2 = (2 * Work) / (Mass)

Final Velocity^2 = (2 * 120,000 J) / (2400 kg)

Final Velocity^2 = 100 J/kg

Taking the square root of both sides, we get:
Final Velocity = sqrt(100 J/kg)

Final Velocity = 10 m/s

Therefore, the speed of the car at the end of 2 seconds is 10 m/s.

17m/s