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October 31, 2014

October 31, 2014

Posted by **Matt** on Sunday, January 24, 2010 at 5:42pm.

[(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]=

-tan²x

I still can't figure this out.

- trig -
**Alyssa**, Sunday, January 24, 2010 at 7:07pmSolve the equation by multiplying, adding, dividing, and subtracting where neccessary. Keep in mind your constants and like terms. Also remember, identity is another way of saying "two sides of an equation that are equal to each other". For example, 2x+0=2x would be identity.

- trig -
**Reiny**, Sunday, January 24, 2010 at 8:03pmcheck your typing, since I can prove that your Left Side = -1

L.S. = [(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]

= cos²x/sin²x - cot²x/cos²x

= cos²x/sin²x - 1/sin²x

= (cos²x - 1)/sin²x

= -sin²x/sin²x

= -1

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