Homework Help: Physics

Posted by Jeremy on Sunday, January 24, 2010 at 2:37pm.

A 10,000 kg railroad car traveling at a speed of 24.0 m/s strikes an identical car at rest. If the cars lock together as a result of the collision, what is their common speed afterward?

Physics - drwls, Sunday, January 24, 2010 at 3:04pm
Apply the law of conservation of momentum to this problem
10,000 * 24.0 = V' * 20,000

V' is the final velocity after collision. Solve for it.

Answer this Question

Related Questions

Physics - A 10,000 kg railroad car traveling at a speed of 24.0 m/s strikes an ...
Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...
Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...
Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...
Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...
Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...
Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides in ...
Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides in ...
physics - How would I graph a collision. i.e if I have a problem A 12,000 kg ...
physics - a 9000 kg railroad car moving at 3 m/s strikes a stationary 5000 kg ...

For Further Reading

First Name:
School Subject:
Answer: