Posted by **Jeremy** on Sunday, January 24, 2010 at 2:34pm.

This is a pretty simple physics problem, but I do not know how to go about it.

How do I:

Show that the time required for a projectile to reach its highest point is equal to the time for it to return to its original height?

- Physics -
**drwls**, Sunday, January 24, 2010 at 3:10pm
The maximum height is where V = 0.

The acceleration rate is -g, in either direction.

The initial speed is the same as the final speed (because of conservation of energy.)

The time it takes to decelerate from initial speed V to 0 is V/g.

The time it takes to accelerate from 0 to -V is also V/g

This works whether the projectile goes straight up or not. V represents the vertical velocity component.

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