how do I solde this equation? pls help..
1. 3/2x + 2 = 1/2 - 1/2x
Hello,
3/2x + 2 = 1/2 - 1/2x
Add 1/2 x to both sides 2x + 2 = 1/2
Subtract 2 from each side:2x = 1/2 - 2 = -3/2
Divide both sides by 2: x = -3/2 divided by 2
= -3/2 * 1/2
= -3/4
thank you =)
From the way you have the equation, it is hard to tell if you mean 3/2 of x or 3 over 2x. If it is the former, post as 3/2 x (with a space). My solution is for the latter possibility.
3/2x + 2 = 1/2 - 1/2x
Multiply both sides by 2x.
3 + 4x = x - 1/2
3x = -7/2
x = -7/6
I hope this helps a little more.
To solve the given equation, you need to isolate the variable x on one side of the equation. Here are the steps to follow:
1. Simplify the equation by getting rid of the fractions, if possible. Multiply through by the least common denominator (LCD) of all the fractions in the equation.
The LCD in this case is 2:
2 * (3/2x + 2) = 2 * (1/2 - 1/2x)
6x + 4 = 1 - x
Now the equation is in a simpler form without fractions.
2. Combine like terms by moving all the terms involving x to one side of the equation.
Move the term "x" to the left side:
6x + x + 4 = 1
Combine the x terms:
7x + 4 = 1
3. Move the constant term to the other side of the equation.
Subtract 4 from both sides:
7x + 4 - 4 = 1 - 4
Simplify:
7x = -3
4. Solve for x by dividing both sides of the equation by the coefficient of x.
Divide both sides by 7:
(7x)/7 = (-3)/7
Simplify:
x = -3/7
Therefore, the solution to the equation is x = -3/7.