1. A girl on a playground swing makes a complete to-and-fro swing each 2 seconds. The frequency of swing is

1. (0.5 hertz)
2. (1hertz) (ANSWER)
3. (2 hertz)
And the period is (FROM THE QUESTION BEFORE)
1. (0.5 seconds) (ANSWER)
2. (1 second)
3. (2 seconds)

2. The period of a 444-hertz sound wave is _____ second(s).
ANSWER: 220

3. A marine weather station reports waves along the shore that are 8 seconds apart. The frequency of the waves is therefore _____ hertz.
ANSWER: 16

4. The annoying sound from a mosquito occurs because it beats its wings at the average rate of 600 wingbeats per second.
( a.) What is the frequency of the soundwaves?
ANSWER: 600 vibrations per second.
( b.) What is the wavelength? (Assume the speed of sound is 340 m/s.)
ANSWER: 0.57 (rounded) meters

5. When an automobile moves towards a listener, the sound of its horn seems relatively _____
1. High pitched (ANSWER)
2. Low pitched
3. Normal
When moving away from the listener, its horn seems ______
1. High pitched
2. Low pitched (ANSWER)
3. Normal

6. The changed pitch of the Doppler Effect is due t changes in_______
1. Wave Speed
2. Wave Frequency (ANSWER)

Thanks so much for the help!!

A child in a swing makes one complete back and forth motion in 4.0 seconds. This statement provides information about the child's.

You're welcome! I'm glad I could help you. If you have any more questions, feel free to ask!

1. To find the frequency of the swing, you need to calculate the number of complete swings per second. In this case, the girl makes one complete to-and-fro swing every 2 seconds. Therefore, the frequency is calculated as the reciprocal of the time taken for one complete swing:

Frequency = 1 / Time
Frequency = 1 / 2
Frequency = 0.5 hertz

2. The period of a wave is the time it takes for one complete cycle. In this case, the period of a 444-hertz sound wave can be calculated using the formula:

Period = 1 / Frequency
Period = 1 / 444
Period = 0.00225 seconds

3. The frequency of waves can be calculated by taking the reciprocal of the time interval between the waves. In this case, the waves are 8 seconds apart, so the calculation would be:

Frequency = 1 / Time
Frequency = 1 / 8
Frequency = 0.125 hertz

4a. The frequency of the soundwaves produced by the mosquito is given as 600 wingbeats per second. Therefore, the frequency of the soundwaves is also 600 vibrations per second.

4b. To calculate the wavelength, we can use the formula:

Wavelength = Speed / Frequency

Given that the speed of sound is 340 m/s and the frequency is 600 vibrations per second, the calculation would be:

Wavelength = 340 / 600
Wavelength = 0.57 meters

5. When an automobile moves towards a listener, the sound of its horn seems relatively high pitched. This is because the frequency of the sound waves increases as the source moves closer to the listener.

When moving away from the listener, its horn seems relatively low pitched. This is because the frequency of the sound waves decreases as the source moves away from the listener.

6. The changed pitch of the Doppler Effect is due to changes in wave frequency. As the source of sound moves towards an observer, the frequency of the sound waves increases, resulting in a higher pitch. Conversely, when the source moves away from the observer, the frequency decreases, resulting in a lower pitch.