A snail climbs up a wall 20 feet high. Each day the snail climbs 5 feet, but each night it slips backwards 4 feet. How many days will it take for the snail to get to the top of the wall?
A snail climb up an electric pole at the rate of 90 cm a day and slips back 60 cm every night, how long will the snail take to reach the top of the a 360 cm high pole?
Ans-90-60=30
30÷360=12
Ans-it will take 12 days
I'm i correct?
Is it 16 or 17? I still do not know as after 15 days the snail is 15 feet up the wall and on the sixteenth day the little fellow gets to 20 feet and sits on top of the wall UNLESS he slides back and finishes at 16 feet and on the 17th day the snail not only reaches 20 feet but also is able to 'climb over the top' and sit on top of the wall.
To determine the number of days it takes for the snail to get to the top of the wall, we can analyze its daily progress.
1. Calculate the net progress made by the snail every day:
- During the day, the snail climbs 5 feet.
- During the night, it slips down 4 feet.
- Therefore, the snail makes a net progress of 5 - 4 = 1 foot per day.
2. Divide the total height of the wall by the net progress made per day:
- The total height of the wall is 20 feet.
- The snail makes a net progress of 1 foot per day.
- Therefore, the snail needs to make 20 / 1 = 20 days to reach the top of the wall.
So, it will take the snail 20 days to get to the top of the wall.
5-4 = 1
The snail only goes up 1 foot a day.
20 * 1 = ?