tarzan tries to cross a river by swinging from one bank to the other on a vine that is 10.0 meters long. his speed at the bottom of the swimg is 8.0 meters/second. Tarzan does not know that the vine has a breaking strnght of 1000 newtons. what is the largest mass that tarzan can have and still make it safely across the river?

physics suck

f = ma FT- Fg = mv^2/r Ft = m(g + V^2/r)

f = 1.0 x 10^3 N Ft - mg = mv^2/r 1000 = m (9.81 + 8^2 /10)
1000N/ 16.21= 62 kg max mass for tarzan

your welcome

Rope tension at lowest point of swing

= M (g + a)

where

a = V^2/R

R = 10.0 m.

If it breaks,

m (g + V^2/R) = 1000 N

Solve for m. They tell you what v is. (It actually depends upon how high up he starts the jump)

you guys suck

To find the largest mass that Tarzan can have and still make it safely across the river, we need to consider the forces at play during the swing.

First, let's determine the maximum tension in the vine when Tarzan is at the bottom of the swing. At the lowest point, Tarzan's weight acts vertically downward and the tension in the vine acts horizontally. The centripetal force that keeps Tarzan moving in a circular path is provided by the tension in the vine.

The centripetal force is given by the equation:

F = m * (v^2 / r)

Where:
F is the centripetal force
m is Tarzan's mass
v is Tarzan's velocity (8.0 m/s in this case)
r is the radius of the circular path (half the length of the vine, since Tarzan swings from one bank to the other)

We can rearrange the equation to solve for m:

m = (F * r) / v^2

The maximum tension that the vine can withstand is its breaking strength, which is given as 1000 Newtons. So we can substitute the values into the equation:

m = (1000 N * 10.0 m) / (8.0 m/s)^2

m = 1250 kg

Therefore, the largest mass that Tarzan can have and still make it safely across the river is 1250 kilograms.

62

Ac = v^2/r = 64/10 = 6.4 m/s^2

total tension = m (9.8+6.4) = 1000
m = 1000/(9.8+6.4)