Posted by Laura on Sunday, January 24, 2010 at 9:17am.
(a) Your acceleration could have been computed more quickly as
a = [v(2) - v(1)] = -5.0 / 25 = -0.2 m/s^2
Note that is it negative.
(b) Force = ma = 1452*(-0.2) = -290 N
(the minus sign means the force is backwards).
(c) To decelerate a car in 3 s from a speed of 25 m/s, the acceleration must be -25/3 = -8.33 m/s^2
-0.2 m/s^2 of that deceleration was due to the aerodynamic force, so the remaining -8.13 m/s^2 must be due to emergency brake friction.
The force applied by the e-brake is
F(eb) = m*a(eb) = -8.13*1452 = -12,100 N
Superwoman is hovering above the ground when a person free-falling goes by her at a terminal velocity of 140km/h. Unfortunately, the parachute does not open. Fortunately, superwoman is around. If it takes her 1.9s to realize the person is in distress, what must her acceleration be if she is to catch the parachutist just before she hits the ground 1000m below?
Related Questions
grade 11 physics - sue drives her 1452 kg car along a straight road at a ...
Physics - A 1100 kg car is moving toward the north along a straight road at a ...
physics - I need help with this question. A car travels along a straight and ...
Physics - Heyy is anybdy good at physics I am stuck on this question ... ... A ...
Physics - A sleepy man drives a car along a straight section of highway at a ...
Physics - A 1100 kg car is moving toward the north along a straight road at a ...
physics - A car starts from rest and accelerates uniformly along a straight ...
Physical Science - A car starts from rest and accelerates uniformly along a ...
Physics - You are driving a 2570.0-kg car at a constant speed of 14.0 m/s along ...
Physics - You are driving a 2570.0-kg car at a constant speed of 14.0 m/s along ...
For Further Reading