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March 27, 2017

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An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 15.0 m if her initial speed is 2.40 m/s. What is the free-fall acceleration on the planet?

  • physics - ,

    The horizontal distance covered is
    X = 2 Vo^2/g sin A cos A
    = (Vo^2/g) * sin (2A)
    where Vo is the initial velocity and A is the takeoff angle.
    Maximum range is obtained with A = 45 degrees. In this case,
    X = Vo^2/g

    Use this equation to solve for g

  • physics - ,

    2.60m/s

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