Posted by **Josh** on Saturday, January 23, 2010 at 5:28pm.

I posted this problem the other day and someone answered it but when I checked my book I realized that I wrote the problem wrong. This morning when I posted I had put the wrong answer. The answer is suppose to be 1/8 but I don't understand how to solve the problem. Help would be greatly appreciated.

(1/4)^2/(1/2-3/4)+ 3/2^3 (It's all one equation)

- Math -
**PsyDAG**, Saturday, January 23, 2010 at 7:06pm
First of all, it is not an equation, since it does not have an equal sign. Second, I think you wanted the sequence to be like this, so it is not just the 2 that is cubed:

(1/4)^2/(1/2-3/4)+ (3/2)^3

(3/2)^3 = 3/2 * 3/2 * 3/2 = 27/8

(1/4)^2 = 1/4 * 1/4 = 1/16

1/2 - 3/4 = -1/4

(1/16)/(-1/4) = (1/16) * -4 = -4/16 = -1/4 = -2/8

-2/8 + 27/8 = 25/8 = 3 1/8

I hope this breaks it down well enough for you to understand.

## Answer this Question

## Related Questions

- Math - I posted this problem the other day and someone answered it but when I ...
- Chemistry - I am working on a problem that was posted January 20. Can someone ...
- Algebra - The answer in the book however says -(5x^2-17x-9)/(x-3)(x+2) so I don'...
- math - word problem. help asap? - in a certain math class, each student has a ...
- Math HELP! - I posted a few questions and then went back and posted how I ...
- Japanese - On thursday I posted a question. I had done most of the work I just ...
- drbob222,math - I've written back for the one i'm having trouble with of the ...
- Anonymous: Re: Grammar - I checked the first 25 answers you posted for your 50-...
- Linear Equation - I posted a question below but forgot to put in the equation! ...
- math,drbob222 - I'm sorry the problems i posted had a couple of errors how i ...

More Related Questions