pete and john play a game of tug f war on a frictionless icy curface. pete weighs 539 N and john weights 392 N. during the course of the game, john accelerates toward pete at a rate of 3 m/s^2
a)what's the magnitude of the force that peter exerts on john?
b)what's the magnitude of pete's acceleration toward john?
I am not sure what formula to use, pleaase help!
The center of mass will remain in the same place in this frictionless situation
a) Use F = ma
Solve for the F
b) Also use F = ma on Pete, with the same F, and solve for a(of Pete).
The F will be the same on both, but in opposite directions.
While John is traveling along an interstate
highway, he notices a 160 mi marker as he
passes through town. Later John passes a
108 mi marker.
What is the distance between town and
John’s current location?
Answer in units of mi
To solve this problem, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, since we are dealing with the force exerted by Pete on John, we'll use the formula:
Force = mass × acceleration
Now let's go through each step to find the answers to the given questions:
a) To find the magnitude of the force that Pete exerts on John, we'll use the given mass and acceleration of John. Since John is accelerating towards Pete, we need to consider the force exerted by Pete as the net force acting on John. Therefore:
Force = mass × acceleration
Force = 392 N × 3 m/s^2
Force = 1176 N
So, the magnitude of the force that Pete exerts on John is 1176 N.
b) To find the magnitude of Pete's acceleration toward John, we'll use the same formula, but this time taking into account Pete's mass and the force between Pete and John. Since Pete and John are pulling towards each other with an equal force (but in opposite directions), we can use the mass and force of either Pete or John interchangeably. Therefore:
Force = mass × acceleration
1176 N = 539 N × acceleration
To solve for acceleration, we rearrange the equation:
acceleration = Force / mass
acceleration = 1176 N / 539 N
acceleration ≈ 2.18 m/s^2
So, the magnitude of Pete's acceleration toward John is approximately 2.18 m/s^2.
In summary:
a) The magnitude of the force that Pete exerts on John is 1176 N.
b) The magnitude of Pete's acceleration toward John is approximately 2.18 m/s^2.