algebra
posted by Diana on .
the width of a rectangle is 1 ft less than the length, the area is 6 ft^2, what is the length and width? thank you

L * (L1) = 6
L^2 L 6 = 0
(L3)(L+2) = 0
take it from there 
L*W=area
L(L1)=6
solve for L
L^2L6=0
(L3)(L+2)=9
L=3, W=2 
thanks bob, for all your help