Monday

July 28, 2014

July 28, 2014

Posted by **kim** on Friday, January 22, 2010 at 12:32pm.

- math -
**Marth**, Friday, January 22, 2010 at 2:15pmTry to come up with 2 combinations of nickels, dimes, and quarters, such that no more than 4 of each are used.

For example: 4 quarters

- math -
**drwls**, Friday, January 22, 2010 at 2:18pmThere can be no pennies and no dimes, becasue they are smaller than a nickel. Also no Kennedy half dollars. That leaves quarters and nickels to make change with. There could be 0, 1, 2 or 3 nickels and 0, 1, 2 or 3 quarters.

See what change you could make with those combinations. There are a lot more than two possiblities.

**Related Questions**

Algergra - I am stumped! I have been working on these problems for the longest ...

English - There is a stranger near the museum. You have to give directions to ...

Math - Can someone help me with this I figured out a similar problem P(x) = ...

Algebra - Once again, I have some confusing problems for math. If you know any ...

Trigonometry (Logarthims) - Give checks to the following two questions Use ...

Chemistry + possible answers - for question 2c earlier - Would you describe the ...

Physics - well, we tried searching up simple physics equations on google, as dr...

math help - Thank you for helping me with the last problem Reiny and Bosnian. ...

math/algebra - I’m working at this restaurant making $30,000 a year. Another ...

Algebra - I have this math probelm z-(3z)/(2-z)=(6)/(z-2) in my book it says to ...