Sunday

November 23, 2014

November 23, 2014

Posted by **Gabe** on Friday, January 22, 2010 at 3:17am.

Find the magnitude, alpha, of the angular acceleration of the cylinder as the block descends.

Express your answer in terms of the cylinder's radius r and the magnitude of the acceleration due to gravity g.

- physics -
**drwls**, Friday, January 22, 2010 at 6:57amLet T be the string tension. That and the angular acceleration alpha are the unknowns. Separate equations for the acceleration of the block and the angular acceleration of the cylinder will allow you to solve for both variables. The moment of inertia of the cylinder in (1/2) M r^2

m g - T = m a

T*r = torque = I*alpha = (1/2) m r^2 * alpha

T = (1/2) m*r*alpha

m g = ma + (1/2) m r * alpha

= ma + (1/2) m a

(since alpha = a/r)

a = (2/3) g

alpha = (2/3)(g/r)

**Answer this Question**

**Related Questions**

physcs - A string is wrapped around a uniform solid cylinder of radius 3.10 cm, ...

Physics - A massless string is wrapped around a cylinder of mass 0.400 kg and ...

Physics - Consider a stainless steel annular disk with an outer radius 66 mm and...

physics - A long string is wrapped around a 6.2cm diameter cylinder, initially ...

Physics - A solid cylinder is mounted above the ground with its axis of rotation...

Physics - A solid cylinder is mounted above the ground with its axis of rotation...

Physics - I need help with this question please. A solid cylinder of mass m and ...

Applied physics - a string is wrapped around a cylinder with radius of 20cm. If ...

Physics - Consider a stainless steel annular disk with an outer radius 68mm and ...

Physics - Consider a stainless steel annular disk with an outer radius 68mm and ...