Tuesday

October 21, 2014

October 21, 2014

Posted by **Julie** on Friday, January 22, 2010 at 1:29am.

- calculus -
**drwls**, Friday, January 22, 2010 at 7:25amLet there be x mL of 65% solution and y mL of 25% solution.

x + y = 384

Amount of acid:

0.50*384 = 192 = 0.65 x + 0.25 y

768 = 2.6 x + y

Subtract the first equation from the third.

1.6 x = 384

x = 240 mL

y = 144 mL

**Answer this Question**

**Related Questions**

college - what quantity x of a 65% acid solution must be mixed with a 20% ...

math - 60 ml of solution A is mixed with 120 ml of solution B to produce ...

Algebra - Suppose a 2% acid solution is mixed with a 3% acid solution. Find the ...

Algebra - Suppose a 2% acid solution is mixed with a 3% acid solution. Find the ...

chemisrty - A solid acid is dissolved in enough water to make 200 ml of a ...

chemistry Who clearly step by step - What per cent of free s03 can be obtained ...

Chemistry - 1. What is the percent by mass of a solution that contains 50 grams ...

MATH - Solution A is 25% and solution B is 40% acid. How many gallons of each ...

sosial studies - When 1.0 L solution Ba (NO3) 2 2.0 M at 25oC is mixed with 1.0 ...

chemistry - A 10% acid solution is to be mixed with a 50% acid solution in order...