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April 1, 2015

April 1, 2015

Posted by **Channing** on Thursday, January 21, 2010 at 4:56pm.

a) Determine the volume of the box as a function of the variable .

b) Use a graphing calculator to approximate the values of that produce a volume of 3858.1875.

c)There are 3 values of that produce the given value but only two of them are acceptable in the context of the problem. List the two answers, to at least one decimal place.

*I don't even know how to start please help!

- 11th grade math -
**Damon**, Thursday, January 21, 2010 at 5:10pmlength of box = 38 - 2x

width of box = 38-2x

volume of box = V = (38-2x)(38-2x)(x)

V = (1444-152x+4x^2)x

V = 1444x -152x^2 +4x^3

that should get you started

- 11th grade math -
**Channing**, Thursday, January 21, 2010 at 6:13pmSO would I set both (1444-152x+4x^2)x

and 1444x -152x^2 +4x^3 equal to 3858.1875 to find part c?

- 11th grade math -
**vianney**, Thursday, February 4, 2010 at 9:49am6x2 - 21xy + 8xz - 28yz.

- 11th grade math -
**david**, Friday, October 8, 2010 at 6:27pmhad this same probem for college pre-calculue couldnt solve B any other way but guess and check/logic x=4.5

- 11th grade math -
**david**, Friday, October 8, 2010 at 6:38pmsecondary largest possible answre is

Answer: x⋅(38-2⋅x)2

Answer: 8.06181572077

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