Posted by Kayla on Thursday, January 21, 2010 at 4:36pm.
Start at xo
While accelerating
v = 35 t
d = 0 + 0t + (35/2) t^2
at x1,t1
v1 = 35 t1
x1 = 17.5 t1^2
------------------------
While coasting
v2=v1= 35 t1 + 0
d = 17.5 t1^2 + (35 t1)t + (1/2)0
at x2,t2
x2 = 17.5t1^2 + 35 t1(t2)
so
17.5 t1^2 + 35 t1 t2 =16350
t1+t2 = 90 so t2 = (90-t1)
solve for t1, t2 then x2 etc
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