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September 23, 2014

September 23, 2014

Posted by **Sandhya** on Thursday, January 21, 2010 at 7:53am.

(a) What is the average speed for the trip?

(b) What is the average velocity for the trip in magnitude and direction?

- physics -
**drwls**, Thursday, January 21, 2010 at 8:53am(a) average speed =

(total distance travelled)/(elapsed time)

= [115*(16/60) + 87*(9/60)]/(25/60)

(You can factor out the 1/60 to make the calculation easier)

= 104.9 km/h

(b) Add the two distances covered vectorially, taking their direction into account. Divide that distance vector by the elapsed time to get the average velocity. Use the component method. The magnitude is the square root of the sum of the squares of the two velocity components

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