Saturday

April 19, 2014

April 19, 2014

Posted by **Sandhya** on Thursday, January 21, 2010 at 7:53am.

(a) What is the average speed for the trip?

(b) What is the average velocity for the trip in magnitude and direction?

- physics -
**drwls**, Thursday, January 21, 2010 at 8:53am(a) average speed =

(total distance travelled)/(elapsed time)

= [115*(16/60) + 87*(9/60)]/(25/60)

(You can factor out the 1/60 to make the calculation easier)

= 104.9 km/h

(b) Add the two distances covered vectorially, taking their direction into account. Divide that distance vector by the elapsed time to get the average velocity. Use the component method. The magnitude is the square root of the sum of the squares of the two velocity components

**Related Questions**

Northern Virginia community college - A speedboat heads west at 104 km/h for 24....

Physics - Henry walks 20 km west forgot his coat, so he turns and heads 13 km ...

Physics - Could someone please review my answers and tell me if I am on the ...

Physics - A bus travels 270 km south along a straight path with an average ...

Physics - A bus travels 340 km south along a straight path with an average ...

physics - A bus travels 250 km south along a straightpath with an average ...

Physics - A train at a constant 44.0 km/h moves east for 42 min, then in a ...

Physics - A train at a constant 41.0 km/h moves east for 28 min, then in a ...

Physics - A train at a constant 44.0 km/h moves east for 42 min, then in a ...

physics - A train at a constant 68.0 km/h moves east for 41 min, then in a ...