Monday

October 20, 2014

October 20, 2014

Posted by **Sandhya** on Thursday, January 21, 2010 at 7:53am.

(a) What is the average speed for the trip?

(b) What is the average velocity for the trip in magnitude and direction?

- physics -
**drwls**, Thursday, January 21, 2010 at 8:53am(a) average speed =

(total distance travelled)/(elapsed time)

= [115*(16/60) + 87*(9/60)]/(25/60)

(You can factor out the 1/60 to make the calculation easier)

= 104.9 km/h

(b) Add the two distances covered vectorially, taking their direction into account. Divide that distance vector by the elapsed time to get the average velocity. Use the component method. The magnitude is the square root of the sum of the squares of the two velocity components

**Answer this Question**

**Related Questions**

Northern Virginia community college - A speedboat heads west at 104 km/h for 24....

physics - A motorist drives south at 26.0 m/s for 3.00 min, then turns west and ...

physics - A motorist drives south at 26.0 m/s for 3.00 min, then turns west and ...

physics - A driver runs to the south at 20 m / s for 3 min, then turns west and ...

Physics - To get to a concert on time, Dakota has to drive 122 miles in 2.00 hrs...

Physics - A train at a constant 41.0 km/h moves east for 28 min, then in a ...

Physics - A train at a constant 44.0 km/h moves east for 42 min, then in a ...

Physics - A train at a constant 44.0 km/h moves east for 42 min, then in a ...

physics - A train at a constant 68.0 km/h moves east for 41 min, then in a ...

physics - A train at a constant 68.0 km/h moves east for 41 min, then in a ...