Predict the Products for the following reactions and write the chemical equation.
Combustion: Liquid Octane, C8H18 burn in oxygen gas.
how would you set this up and predict the product?
Thnx in advance whoever figures it out :)
Octane is a hydrocarbon (hydrogen and carbon only). When reacted with oxygen, the C is burned to CO2 and the hydrogen in burned to H2O. So the products of octane are CO2 and H2O.
To predict the products and write the chemical equation for the combustion reaction of liquid octane (C8H18) with oxygen gas (O2), follow these steps:
1. Write the balanced chemical equation for the combustion reaction:
C8H18 + O2 → CO2 + H2O
2. Determine the stoichiometric coefficients:
In this case, balancing the equation is not necessary as the octane and oxygen are already in the correct ratio for combustion.
3. Identify the reactants and products:
Reactants: Liquid octane (C8H18) and oxygen gas (O2).
Products: Carbon dioxide gas (CO2) and water vapor (H2O).
4. Determine the number of atoms in the reactants and products:
Octane (C8H18) has 8 carbon (C) atoms, 18 hydrogen (H) atoms, and no oxygen (O) atoms. Oxygen gas (O2) has 2 oxygen (O) atoms. Carbon dioxide gas (CO2) has 1 carbon (C) atom and 2 oxygen (O) atoms. Water vapor (H2O) has 2 hydrogen (H) atoms and 1 oxygen (O) atom.
5. Check the number of atoms on both sides of the equation:
On the left side, there are 8 carbon (C) atoms, 18 hydrogen (H) atoms, and 2 oxygen (O) atoms. On the right side, there are also 8 carbon (C) atoms, 18 hydrogen (H) atoms, and 2 oxygen (O) atoms.
Therefore, the predicted products for the combustion reaction of octane (C8H18) with oxygen gas (O2) are carbon dioxide (CO2) and water (H2O), and the balanced chemical equation is:
C8H18 + 12.5 O2 → 8 CO2 + 9 H2O