The sum of the diameters of two circles is 28 inches. One circle has a diameter that is 8 inches longer than the diameter of the other. What are the diameters of the two circles?

x+d=28

x=d-8

try it from there do you know how to do system of equailets? think of x as one of your diameters and d as the other.
plug in the second equation to the top one lik this:
(d-8)+d=28 then find x and check it by plugging in the number. hope this helps (:

To find the diameters of the two circles, we can set up a system of equations based on the given information.

Let's assume the diameter of one circle is "x" inches. Since the diameter of the other circle is 8 inches longer, its diameter will be "x + 8" inches.

According to the problem, the sum of the diameters of the two circles is 28 inches. So, we can write the equation:

x + (x + 8) = 28

Simplifying the equation:
2x + 8 = 28

Now, we can solve for x by subtracting 8 from both sides of the equation:
2x = 20

Dividing both sides by 2:
x = 10

Therefore, the diameter of one circle is 10 inches, and the diameter of the other circle (which is 8 inches longer) is:
10 + 8 = 18 inches.

So, the diameter of the two circles is 10 inches and 18 inches, respectively.