Posted by **Kaitlyn** on Wednesday, January 20, 2010 at 10:29pm.

Susan has red, blue, green, and yellow sweaters. Joanne has green, red, purple, and white sweaters. Diane's sweaters are red, blue, purple, and mauve. Each girl has only one sweater of each color, and will pick a sweater to wear at random. Find each probability.

P(each girl chooses a different color)

P(each girl chooses the same color)

P(two girls choose the same color, and the third chooses a different color)

P(each girl chooses a red sweater)

- 7th grade -
**Jake**, Tuesday, June 1, 2010 at 6:35pm
8)>>>Write a group of 3 rows for girl names and and 7 columns for colors

Each girl chooses the same color (easiest)

The only color they can choose is red.

(1/4)^3=1/64

.

9)>>>> P(two girls choose the same color, and the third chooses a different color)

for susan chooses red & another picks red: 2(1/4 * 1/4 * 3/4) =============6/64

for susan chooses red & and both others pick purple: 1/4 * 1/4 * 1/4=======1/64

for susan chooses blue & Diane picks blue: 1/4 * 1/4 * 4/4=================4/64

for susan chooses blue & and both others pick purple or red:1/4*2/4*1/4====2/64

for susan chooses green & Joanne picks green: 1/4 * 1/4 * 4/4==============4/64

for susan chooses green & and both others pick purple or red:1/4*2/4*1/4===2/64

for susan chooses yellow & and both others pick purple or red:1/4*2/4*1/4==2/64

total: 21/64

.

10)>>> For each chosing a different color.

1-22/64=42/64=21/32

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