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January 30, 2015

January 30, 2015

Posted by **allan** on Wednesday, January 20, 2010 at 8:31pm.

- math -
**Erica**, Wednesday, January 20, 2010 at 9:28pmSo you need to make two equations, and then use substitution.

I used A for the larger number and B for the smaller:

A=B+5

4A+3B=97

Then you plug in (B+5) for A in the second equation...

4(B+5)+3B=97

4B+20+3B=97

7B+20=97

7B=77

B=11

A=5+11

A=16

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