Posted by allan on Wednesday, January 20, 2010 at 8:31pm.
So you need to make two equations, and then use substitution.
I used A for the larger number and B for the smaller:
A=B+5
4A+3B=97
Then you plug in (B+5) for A in the second equation...
4(B+5)+3B=97
4B+20+3B=97
7B+20=97
7B=77
B=11
A=5+11
A=16
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