Posted by Josh on Wednesday, January 20, 2010 at 7:01pm.
Find all the points having an x coordinate of 2 whose distance from the point (1,5) is 5.
so far i have
5=sqrt((12)^2+(2y)^2)
5=(3)^2
how do i simplify the rest of the equation so i can find x. do i foil it out? thanks.

Trig/Math  MathMate, Wednesday, January 20, 2010 at 8:09pm
Geometrically, you are looking for the intersection of a vertical line (x=2) with a circle centred at (1,5) with a radius of 5.
Line L1: x=2
Circle C1: (x(1))²+(y(5))²=5²
(x+1)²+(y+5)²=25
Substitute x=2 in C1:
(2+1)²+(y+5)²=25
(y+5)²=253²=16=4²
(y+5) = ±4
So there are two solutions, y=9 or y=1

Trig/Math  Josh, Wednesday, January 20, 2010 at 10:27pm
thank you!!

Trig/Math :)  MathMate, Thursday, January 21, 2010 at 12:11am
You're welcome.
Do give a check on the distance between the centre and the intersection points to complete the question.
Answer This Question
Related Questions
 math  Find all the points having an xcoordinate of 9 whose distance from the ...
 Advanced Math  find all points having an xcoordinate of 2 whose distance of ...
 Algebra  find all points having an xcoordinate of 4 whose distance from the ...
 Math  Find all points having xcoordinate 9 and distance 10 from the point (3,...
 mathInverse functions  f(x)=4x2 & g(x)=5x6. Find (f*g) and state domain. f(...
 ????Math Question????8th grade adv.math  Algebra! How is the distance formula ...
 Calculus  the curve: (x)(y^2)(x^3)(y)=6 (dy/dx)=(3(x^2)y(y^2))/(2xy(x^3)) a...
 Math  I have a series of questions that I did. They lead up to the last ...
 Math (Analytic Geometry)  1. Find the equation of the set of all points P(x,y) ...
 math  Alright, let's say you want to get from one point to another, in a 3D box...
More Related Questions