i know that the slop intercept form is
y-y1=m(x-x1)
i have to write an equation for a line that has a slope of 6 and contains the point (-8,-7) even with the formula i don't now how, HELP!!!!
the x1 and y1 are the values of your given point, so just sub them in
y-y1=m(x-x1)
y - (-8) = 6(x - (-7))
y + 8 = 6(x + 7)
y + 8 = 6x + 42
y = 6x + 34
BTW, the formula you gave is generally called the slope-point form
the final version I gave you has the form
y = mx + b, which is called the slope-intercept form
i just realized the error thank you!
To write an equation for a line that has a slope of 6 and contains the point (-8, -7) using the slope-intercept form, you can follow these steps:
Step 1: Understand the equation form
The slope-intercept form of a linear equation is: y = mx + b, where:
- "m" represents the slope of the line
- "b" represents the y-intercept (the point where the line crosses the y-axis)
Step 2: Identify the given information
From the problem, you know:
- The slope (m) is 6
- The line passes through the point (-8, -7)
Step 3: Substitute the known values into the equation
Substitute the values of the slope (m) and the coordinates of the given point (-8, -7) into the equation:
y = mx + b
So, we have: -7 = 6(-8) + b
Step 4: Solve for the y-intercept (b)
Now, let's solve for the y-intercept (b). First, distribute the 6:
-7 = -48 + b
To isolate "b", add 48 to both sides of the equation:
-7 + 48 = b
41 = b
Step 5: Write the final equation
Now that we have the value of the y-intercept (b), substitute it back into the equation:
y = 6x + 41
So, the equation for the line with a slope of 6 and passing through the point (-8, -7) is y = 6x + 41.