Posted by mary on Monday, January 18, 2010 at 8:22pm.
27Al13 + ? yields 30P15 + 1n0
Subscripts must add out.
Superscripts must add out.
I am changing it to show the atomic number first and mass second.
13Al27 + ?? ==>15P30 + 0n1
13 + ? = 15 + 0 so ? must be 2
27 + ? = 30 + 1 so ? must be 4
What do you know that has an atomic number of 2 and an atomic mass of 4. That must be He or written as I have done it, make it 2He4.
That's how it's done.
Thank you so much for your help!
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