Two dice are rolled. Find the odds in favor of a sum of 6.
lets see. YOu can get 36 different combinations.
Of those, the ways to get six are
1,5
2,4
3,3
4,2
5,1
So five ways to get sum of six, 31 ways of not getting a sum of six.
odds is ways to get it, divided by ways not to get it.
Odds= 5:31 of getting a six total
To find the odds in favor of a sum of 6 when two dice are rolled, we need to determine the number of favorable outcomes (sum of 6) and divide it by the total number of possible outcomes when two dice are rolled.
To determine the number of favorable outcomes, we need to find how many combinations of two numbers from 1 to 6 sum up to 6.
The following combinations yield a sum of 6:
- (1, 5)
- (5, 1)
- (2, 4)
- (4, 2)
- (3, 3)
So, there are 5 favorable outcomes for a sum of 6.
To find the total number of possible outcomes, we need to consider that each dice has 6 possible outcomes (numbers 1 to 6), and since there are two dice, the total number of outcomes is 6 x 6 = 36.
Therefore, the odds in favor of a sum of 6 can be calculated as the ratio of favorable outcomes to total outcomes:
Odds in favor of a sum of 6 = Favorable outcomes / Total outcomes
Odds in favor of a sum of 6 = 5 / 36
So, the odds in favor of a sum of 6 when two dice are rolled are 5 to 36.