College chemistry
posted by eddie on .
How much heat (in kJ) is evolved in converting 1.00 mol of steam at 130.0 C to ice at 50.0 C? The heat capacity of steam is 2.01 J/g*C and of ice is 2.09 J/g*C.

You must go through all of the steps from steam at 130 to ice at 50.
q to move steam at 130 to steam at 100.
q1 = mass x specific heat x delta T.
q to convert steam at 100 to liquid water at 100.
q2 = mass x heat of vaporization.
q to move water at 100 to water at zero.
q3 = mass x specific heat x delta T.
q to convert water at zero to ice at zero.
q4 = mass x heat of fusion.
q to move ice at zero to ice at 50.
q5 = mass x specific heat x delta T.
Then total q =
q1+q2+q3+q4+q5.
I notice your specific heats are listed in joules so your answer will come out in Joules and you must convert to kJ since the problem asks for kJ. 
55.078

57 kj