Posted by Kate on .
A fisherman's scale stretches 2.8 cm when a 3.7kg fish hangs from it. (a) What is the spring constant? (b) What will be the amplitude and frequency of vibration fi the fish is pulled down 2.5 cm more and released so that it vibrates up and down?
I have a question about finding the frequency. For some reason I keep on getting ((3.7 / 129.5)^.5) / (2 * pi) = 0.0269020955 that for my answer but the back of the book says 3.0 hz

jishka, Math 
GuruBlue,
please put the subject in the subject line.

physics 
Kate,
i did for some reason it changes it

jishka 
Damon,
3.7kg * 9.8 = 36.26 N
stretch distance = .028 m
so
k = 36.26/.028 = 1295 N/m
F = m a
kx = m a
if x = A cos 2pi f t
a = A (2 pi f)^2 cos 2 pi f t
so
k A cos 2 pi f t = mA (2 pi f )^2 cos 2 pi f t
(2 pi f)^2 =k/m
(2 pi f)^2 = 1295/3.7 = 350
2 pi f = 18.7
f = 2.98 Hz 
ap history 
heather,
was the new Deal essentially a conservative attempt to save American capitalism from collapse, a radical change in traditional American antigovernment beliefs, or a moderate liberal response to a unique crisis? please help i tried reading but confuse. im leaning towards conservative attempt. need help badly before monday. thanks so much.