Posted by **Michelle** on Sunday, January 17, 2010 at 2:16pm.

The areas of the faces of a rectangle box are 48 m2, 96 m2, and 288 m2. A second box is cubical and each of its faces has area 16m2. Find the ratio of the volume of the first box to the volume of the second box.

- Math -
**Reiny**, Sunday, January 17, 2010 at 2:33pm
how about letting the 3 lengths of the first cube be a, b, and c

then

ab = 288

ac = 96

bc = 48

from that you could do stuff like

ab/(ac) = 288/96

b/c = 3

b = 3c

using other variations, and subbing back, I found

a = 24

b = 12

c = 4 (the side areas check out)

so the volume of the first is .....

I am sure you can finish it.

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