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September 19, 2014

September 19, 2014

Posted by **Michelle** on Sunday, January 17, 2010 at 2:16pm.

- Math -
**Reiny**, Sunday, January 17, 2010 at 2:33pmhow about letting the 3 lengths of the first cube be a, b, and c

then

ab = 288

ac = 96

bc = 48

from that you could do stuff like

ab/(ac) = 288/96

b/c = 3

b = 3c

using other variations, and subbing back, I found

a = 24

b = 12

c = 4 (the side areas check out)

so the volume of the first is .....

I am sure you can finish it.

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